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10 papers
Indices of Maximal Subgroups of Finite Soluble Groups
V. S. Monakhov Francisk Skorina Gomel State University
Abstract:
We look at the structure of a soluble group
$G$ depending on the value of a function
$m(G)=\max\limits_{p\in\pi(G)}$, where $m_p(G)=\max\{\log_p|G:M|\mid M<_{\max}G,\ |G:M|=p^a\}$,
$p\in \pi (G)$.
\medskip
Theorem 1. {\it States that for a soluble group
$G$, (1)
$r(G/\Phi (G))=m(G)$; (2) $d(G/\Phi (G))\leqslant1+\rho(m(G))\leqslant3+m(G)$; (3)
$l_p(G)\leqslant1+t$, where
$2^{t-1}<m_p(G)\leqslant 2^t$.}
\medskip
Here,
$\Phi(G)$ is the Frattini subgroup of
$G$, and
$r(G)$,
$d(G)$, and
$l_p(G)$ are, respectively, the principal rank, the derived length, and the
$p$-length of
$G$. The maximum of derived lengths of completely reducible soluble subgroups of a general linear group
$GL(n,F)$ of degree
$n$, where
$F$ is a field, is denoted by
$\rho(n)$. The function
$m(G)$ allows us to establish the existence of a new class of conjugate subgroups in soluble groups. Namely,
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Theorem 2. {\it Maintains that for any natural
$k$, every soluble group
$G$ contains a subgroup
$K$ possessing the following properties: (1)
$m(K)\leqslant k$; (2) if
$T$ and
$H$ are subgroups of
$G$ such that
$K\leqslant T<_{\max}H\leqslant G$ then
$|H:T|=p^t$ for some prime
$p$ and for
$t>k$. Moreover, every two subgroups of
$G$ enjoying (1) and (2) are mutually conjugate.}
Keywords:
finite soluble group, maximal subgroup.
UDC:
512.542 Received: 20.10.2002