This article is cited in
7 papers
Finite $p$-groups admitting $p$-automorphisms with few fixed points
E. I. Khukhro Sobolev Institute of Mathematics, Siberian Branch of the Russian Academy of Sciences
Abstract:
The following theorem is proved: if a finite
$p$-group
$P$ admits an automorphism of order
$p^k$ having exactly
$p^n$ fixed points, then it contains a subgroup of
$(p, k,n)$-bounded index that is solvable of
$(p,k)$-bounded derived length. The proof uses Kreknin's theorem stating that a Lie ring admitting a regular (that is, without nontrivial fixed points) automorphism of finite order
$m$, is solvable of
$m$-bounded derived length
$f(m)$. Some techniques from the theory of powerful
$p$-groups are also used, especially, from a recent work of Shalev, who proved that, under the hypothesis of the theorem, the derived length of
$P$ is bounded in terms of
$p$,
$k$, and
$n$. The following general proposition is also used (this proposition is proved on the basis of Kreknin's theorem with the help of the Mal'tsev correspondence, given by the Baker–Hausdorff formula): if a nilpotent group
$G$ of class
$c$ admits an automorphism
$\varphi$ of finite order
$m$, then, for some
$(c,m)$-bounded number
$N=N(c,m)$, the derived subgroup
$(G^N)^{(f(m))}$ is contained in the normal closure
$\langle C_G(\varphi)^G\rangle$ of the centralizer
$C_G(\varphi)$. The scheme of the proof of the theorem is as follows. Standard arguments show that
$P$ may be assumed to be a powerful
$p$-group. Next, it is proved that
$P^{f(p^k)}$ is nilpotent of
$(p,k,n)$-bounded class. Then the proposition is applied to
$P^{f(p^k)}$. There exist explicit upper bounds for the functions from the statement of the theorem.
UDC:
512.542.3
MSC: 20D15,
20D45 Received: 28.09.1992