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JOURNALS // Trudy Matematicheskogo Instituta imeni V.A. Steklova // Archive

Trudy Mat. Inst. Steklova, 2012 Volume 277, Pages 57–73 (Mi tm3386)

On the combinatorial structure of Rauzy graphs

M. B. Dubashinsky

Chebyshev Laboratory, St. Petersburg State University, St. Petersburg, Russia

Abstract: Let $S_m^0$ be the set of all irreducible permutations of the numbers $\{1,\dots,m\}$ ($m\ge3$). We define Rauzy induction mappings $a$ and $b$ acting on the set $S_m^0$. For a permutation $\pi\in S_m^0$, denote by $R(\pi)$ the orbit of the permutation $\pi$ under the mappings $a$ and $b$. This orbit can be endowed with the structure of an oriented graph according to the action of the mappings $a$ and $b$ on this set: the edges of this graph belong to one of the two types, $a$ or $b$. We say that the graph $R(\pi)$ is a tree composed of cycles if any simple cycle in this graph consists of edges of the same type. An equivalent formulation of this condition is as follows: a dual graph $R^*(\pi)$ of $R(\pi)$ is a tree. The main result of the paper is as follows: if the graph $R(\pi)$ of a permutation $\pi\in S_m^0$ is a tree composed of cycles, then the set $R(\pi)$ contains a permutation $\pi_0\colon i\mapsto m+1-i$, $i=1,\dots,m$. The converse result is also proved: the graph $R(\pi_0)$ is a tree composed of cycles; in this case, the structure of the graph is explicitly described.

UDC: 519.172.4

Received in November 2011


 English version:
Proceedings of the Steklov Institute of Mathematics, 2012, 277, 51–66

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